Daily 5 Math Practice: 29 Oct Worked Solutions

Five questions do not look like much. Done regularly, though, a short set tends to keep methods fresher than one long session now and then, and it leaves time to talk about the one question that went wrong. That conversation is often where the real learning happens. Here you will find the five questions from each Daily 5 video in this set, Primary 2 to Primary 6, matched to the video, with every hint and worked step kept inside a fold so nothing is given away early. Treat it as a quick routine: try, check, and talk through one step together.

Choose your child's grade below and start with the video. Let them try the five questions on paper before opening anything. Each fold holds the hints first and the answer last, so they can read one hint, have another go, then check their working step by step.

Primary 2 (P2) Math: Whole Numbers, Statistics, Money

This P2 set covers adding three-digit numbers, two picture graphs where each symbol stands for more than one book, writing a dollar amount in cents, and adding dollars and cents. On each graph, ask your child to find the key and say what one symbol is worth before counting. In the money questions, have them read each amount aloud in dollars and cents first.

Primary 2 (P2) Daily 5 video for 29 Oct. Watch it, then try the five questions below before opening any solution.

Question 1 · Addition and Subtraction · easy

392 + 423 =

Show the worked solution

Hint 1

Add the ones digit first:

2 + 3 = 5

Hint 2

Add the tens and hundreds next, regrouping/renaming where necessary

Answer: 815

Question 2 · Picture Graphs with Scales · easy

The picture graph shows books read. How many more books were read on Thursday than on Monday?

Books Read

1 picture = 5 books

Monday

Tuesday

Wednesday

Thursday

Show the worked solution

Hint 1

Count the symbols for Thursday and for Monday.

Hint 2

Each symbol is worth 5 books. Multiply each row's symbol count by 5, then compare the two amounts.

Final step

Thursday:

8 \times 5 = 40

; Monday:

6 \times 5 = 30

; subtract:

40 - 30 = 10

→ 10

Answer: 10

Question 3 · Picture Graphs with Scales · easy

The picture graph shows books read. How many books were read on Wednesday?

Books Read

1 picture = 4 books

Monday

Tuesday

Wednesday

Thursday

Show the worked solution

Hint 1

In this graph, one symbol stands for more than one thing. Multiply the symbols by what one symbol is worth.

Hint 2

Try this: Ravi's chart shows

7

symbols, and each symbol means

2

cans. That makes

7 \times 2 = 14

cans

→ 14.

Final step

Count the symbols for Wednesday, then multiply the count by 4

→ 16

Answer: 16

Question 4 · Dollars and cents · easy

Express

$2.80

in cents.

Show the worked solution

Hint 1

Convert dollars to cents using

1 \text{ dollar} = 100 \text{ cents}

Hint 2

Change the dollars:

2 \times 100 = 200

→ 200 cents.

Final step

Add the cents:

2 \times 100 + 80 = 280

→ 280

Answer: 280

Question 5 · Dollars and cents · easy

$20.20 + $10.00 =

Show the worked solution

Hint 1

Add the dollars:

20 + 10 = 30

Hint 2

Add the cents: 20 cents

Answer: 30.20

Primary 3 (P3) Math: Statistics, Area and Perimeter, Whole Numbers

The P3 questions include reading a bar graph, the perimeter of a rectangle, naming the digit in a given place of a four-digit number, adding four-digit numbers in a story about apples, and a harder problem about rice measured in kilograms and grams. On the bar graph, read the scale carefully. Before subtracting in the rice question, check that every mass is written in the same unit.

Primary 3 (P3) Daily 5 video for 29 Oct. Watch it, then try the five questions below before opening any solution.

Question 1 · Bar Graphs · easy

The bar graph shows transport to school. How many students are recorded for Car?

Transport to School

Show the worked solution

Hint 1

Find the bar for Car in the graph.

Hint 2

Read the value on the scale

Answer: 38

Question 2 · Area and Perimeter · easy

A rectangle has a length of

14\text{ cm}

and a width of

10\text{ cm}

. Find its perimeter.

Show the worked solution

Hint 1

Perimeter of rectangle =

2 \times (\text{Length} + \text{Width})

\text{Length} + \text{Width} + \text{Length} + \text{Width}

Hint 2

Perimeter =

14 + 10 + 14 + 10

Answer: 48

Question 3 · Numbers up to 10,000 · easy

In the number

2356

, which digit is in the hundreds place?

Show the worked solution

Hint 1

Look at the places in the number

2356

: thousands, hundreds, tens, ones.

Hint 2

Identify the digit in the hundreds place

Answer: 3

Question 4 · Addition and Subtraction · medium

A fruit stall sold

3925

apples in the morning and

2658

apples in the afternoon. How many apples were sold in all?

Show the worked solution

Hint 1

Split both amounts into thousands, hundreds, tens, and ones.

Hint 2

Add the thousands parts:

3000 + 2000 = 5000

→ 5000.

Final step

Add the full amounts:

3925 + 2658 = 6583

→ 6583

Answer: 6583

Question 5 · Measurement · hard

A bag of rice weighs

6\text{ kg } 706\text{ g}

. Mrs. Lee uses

1689\text{ g}

on Monday and

1182\text{ g}

on Tuesday. What is the mass of the rice left in grams?

Show the worked solution

Hint 1

Convert the whole thousands and leftover units:

6 \times 1000 + 706

Hint 2

Subtract the first amount from that total:

6 \times 1000 + 706 - 1689

Final step

Then subtract the second amount:

6 \times 1000 + 706 - 1689 - 1182 = 3835

→ 3835

Answer: 3835

Primary 4 (P4) Math: Whole Numbers, Fractions, Area and Perimeter

This P4 set covers subtracting from a four-digit number, finding the part left after a fraction of a set is given away, rounding to the nearest hundred, a perimeter problem where the length and width are linked, and a harder shopping problem about bags of pears. For the perimeter question, a quick labelled sketch helps your child see how the sides make up the whole perimeter.

Primary 4 (P4) Daily 5 video for 29 Oct. Watch it, then try the five questions below before opening any solution.

Question 1 · Operations · easy

Find the value of

2,551 - 161

Show the worked solution

Hint 1

Subtract

161

from

2551

, regrouping across place values where needed.

Hint 2

Check your working column by column

Answer: 2390

Question 2 · Fraction of a Set · medium

Mrs. Lee had

48

stamps. She gave

\frac{3}{4}

of them to her brother. How many stamps did she have left?

Show the worked solution

Hint 1

Find the part given away by splitting this question's total into

4

equal groups and taking

3

of them.

Hint 2

After taking

3

of the

4

equal groups, find the value of the groups left using this question's total.

Final step

Given away:

48 \div 4 \times 3 = 36

. Left:

48 - 36 = 12

→ 12

Answer: 12

Question 3 · Rounding and Estimation · medium

Round

16,234

to the nearest hundred.

Show the worked solution

Hint 1

Look at the digit in the tens place

→ 3.

Hint 2

If it is 5 or more, round up. Otherwise, round down

Answer: 16200

Question 4 · Area and Perimeter · hard

The length of a rectangle is twice its width. If the perimeter is

18\text{ cm}

, what is the width?

Show the worked solution

Hint 1

The length is twice the width.

Hint 2

The length contributes 2 width-parts

→ 2 parts.

Final step

Each half has

2 + 1 = 3

width-parts. Full perimeter has

2 \times 3 = 6

width-parts. Width:

18 \div 6 = 3

→ 3

Answer: 3

Question 5 · Word Problems · hard

A shop sells pears in two ways: a small bag of

3

pears for

$3.00

, or a big bag of

6

pears for

$5.62

. Mrs Tan needs at least

12

pears. What is the least amount she must spend, buying only whole bags?

Show the worked solution

Hint 1

Find how many whole bags each option needs.

Hint 2

A big bag holds

6 \div 3 = 2

times as many pears

→ $2$ . Divide the $12$ -pear demand by each bag size and round up.

Final step

Small bags:

4 \times $3.00 = $12.00

. Big bags:

2 \times $5.62 = $11.24

. The big bags cost less

→ 11.24

Answer: 11.24

Primary 5 (P5) Math: Rate, Ratio, Geometry

The P5 questions cover a rate problem, sharing a total in a given ratio, the area of a parallelogram, rounding a seven-digit number to the nearest hundred thousand, and the area of a trapezium. For both area questions, check which measurement is the height before multiplying. In the rounding question, ask your child to point to the place they are rounding to first.

Primary 5 (P5) Daily 5 video for 29 Oct. Watch it, then try the five questions below before opening any solution.

Question 1 · Rate Word Problems · easy

A machine fills boxes with bottles at

18

bottles per minute. How many bottles does it fill in

10

minutes?

Show the worked solution

Hint 1

Rate

= 18

bottles per minute.

Hint 2

Total

= 18 \times 10

Answer: 180

Question 2 · Ratio Word Problems · easy

red and blue beads are in the ratio

3 : 5

. There are

40

beads in total. How many are red?

Show the worked solution

Hint 1

Add the ratio numbers:

3 + 5 = 8

total parts

→ 8 parts.

Hint 2

One part is

40 \div 8 = 5

→ 5.

Final step

Reuse that one-part value for red:

3 \times 5 = 15

beads

→ 15

Answer: 15

Question 3 · Area of Parallelogram · medium

A piece of land is shaped like a parallelogram. Its base is

9\text{ m}

and its height is

4\text{ m}

. What is the area?

Show the worked solution

Hint 1

Area of parallelogram

=

base

\times

height.

Hint 2

9 \times 4

Answer: 36

Question 4 · Rounding · medium

Round

1,005,597

to the nearest hundred thousand.

Show the worked solution

Hint 1

Identify the digit in the hundred thousand place.

Hint 2

Look at the digit to its right. If it is 5 or more, round up. If it is less than 5, round down

Answer: 1000000

Question 5 · Area of Trapezium · medium

A trapezium has parallel sides of

6\text{ cm}

and

10\text{ cm}

, and a height of

4\text{ cm}

. Find its area.

Show the worked solution

Hint 1

Area of trapezium

= \frac{1}{2} \times (a + b) \times h

, where

a

and

b

are the parallel sides.

Hint 2

= \frac{1}{2} \times (6 + 10) \times 4 = \frac{1}{2} \times 16 \times 4

Answer: 32

Primary 6 (P6) Math: Whole Numbers, Algebra, Ratio

This P6 set opens with a calculator error problem and an algebraic expression to evaluate, then moves to two ratio problems, one comparing two rods on a diagram and one with a before-and-after change, and ends with a fraction problem about keychains. In the algebra question, substitute carefully and follow the order of operations. In each ratio question, write the units before and after any change.

Primary 6 (P6) Daily 5 video for 29 Oct. Watch it, then try the five questions below before opening any solution.

Question 1 · Calculator Error Problems · medium

Jason used a calculator to divide a 4-digit number by a 1-digit number. For the 1-digit number, he made a mistake by pressing

5

instead of

3

. He obtained an incorrect answer of

255

. What should be the correct answer?

Show the worked solution

Hint 1

Work backwards: multiply the wrong answer by the divisor that was pressed.

Hint 2

The dividend is

255 \times 5

Final step

255 \times 5 = 1275

, then divide by 3:

1275 \div 3 = 425

→ 425

Answer: 425

Question 2 · Evaluating Algebraic Expressions · medium

Find the value of

7w - \frac{8w}{3} + 2

when

w = 12

Show the worked solution

Hint 1

Substitute

w = 12

into the expression:

7(12) - \frac{8(12)}{3} + 2

Hint 2

Multiply:

7 \times 12 = 84

Final step

Combine:

84 - 32 + 2 = 54

→ 54

Answer: 54

Question 3 · Ratio with Offset Bar Models · hard

The figure shows two rods drawn between the same two dashed lines. The ratio of the length of rod M to the length of rod N is

8 : 5

. Find the length of rod N in metres.

Show the worked solution

Hint 1

Both rods span the same two dashed lines. Their labels show

3.7

m and

1.6

m; subtract these gaps.

Hint 2

The ratio counts differ by

8 - 5 = 3

units. Divide the length difference by this count to find one unit.

Final step

Labels differ by

3.7 - 1.6 = 2.1

m. One unit is

2.1 \div 3 = 0.7

m. Rod N has 5 units:

5 \times 0.7 = 3.5

→ 3.5

Answer: 3.5

Question 4 · Before & After Problems · hard

The ratio of boys to girls in a hall was

4:5

. After

14

boys left the hall, the ratio became

2:5

. How many girls were there?

Show the worked solution

Hint 1

Girls do not change, so keep their units fixed. The boys' change in units equals the number who left.

Hint 2

Boys' units drop from

4

2

4 - 2 = 2

units. This change equals 14 boys, so

14 \div 2 = 7

per unit.

Final step

Girls stay at

5

units:

5 \times 7 = 35

→ 35

Answer: 35

Question 5 · Fraction Word Problems (Ratio and Remainder) · hard

Priya made some red and blue keychains. At first, the number of red keychains was

\frac{3}{4}

the number of blue keychains. She gave away

\frac{1}{3}

of the red keychains and

\frac{1}{4}

of the blue keychains. Then she had

20

more blue keychains than red keychains. How many keychains did Priya make in all?

Show the worked solution

Hint 1

1 - \frac{1}{3} = \frac{2}{3}

;

\frac{2}{3} \times \frac{3}{4} = \frac{1}{2}

and

1 - \frac{1}{4} = \frac{3}{4}

are the red and blue keychains left.

Hint 2

Their difference is

\frac{3}{4} - \frac{1}{2} = \frac{1}{4}

of the blue keychains, or

20

keychains.

Final step

20 \div (\frac{1}{4}) = 80

blue keychains;

\frac{3}{4} \times 80 = 60

red keychains;

80 + 60 = 140

→ 140

Answer: 140

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Category	Symbols
Monday	6 symbols
Tuesday	2 symbols
Wednesday	5 symbols
Thursday	8 symbols

Category	Symbols
Monday	2 symbols
Tuesday	3 symbols
Wednesday	4 symbols
Thursday	5 symbols

Category	Value
Bus	18 students
Car	38 students
Train	16 students
Walk	36 students

Daily 5 Math Practice: 29 Oct Worked Solutions

Try what you just learned

Primary 2 (P2) Math: Whole Numbers, Statistics, Money

Books Read

Books Read

Primary 3 (P3) Math: Statistics, Area and Perimeter, Whole Numbers

Transport to School

Primary 4 (P4) Math: Whole Numbers, Fractions, Area and Perimeter

Primary 5 (P5) Math: Rate, Ratio, Geometry

Primary 6 (P6) Math: Whole Numbers, Algebra, Ratio

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